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Old 19 December 2012, 10:28 AM   #1
thxbuff2001
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Tudor 7928 Submariner

I just bought a Tudor 7928 Submariner. The movement is inscribed 390. I was tinkering with it and it does not quick set?

Are Tudor 7928 submariners quick sets or not?
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Old 19 December 2012, 10:49 AM   #2
joe100
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Mine wasn't if I remember correctly.
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Old 19 December 2012, 12:37 PM   #3
thxbuff2001
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thanks.

Did not realize it until I got it and was surprised to see it was not a quickset.
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Old 19 December 2012, 01:51 PM   #4
tudorman8276
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...hmmm...

...first off, NO Tudor 7928 had a date to mess with.

...sooooooo, what do you mean by quick set?????
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Old 19 December 2012, 01:58 PM   #5
Brenngun
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As mentioned by Stan should not have a date function. Got any pics?
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Old 19 December 2012, 02:26 PM   #6
Frogman4me
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Quote:
Originally Posted by tudorman8276 View Post
...first off, NO Tudor 7928 had a date to mess with.

...sooooooo, what do you mean by quick set?????
+1

Need pics
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Old 19 December 2012, 03:12 PM   #7
thxbuff2001
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Quote:
Originally Posted by tudorman8276 View Post
...first off, NO Tudor 7928 had a date to mess with.

...sooooooo, what do you mean by quick set?????

You're right.

Come to think of it, this is the first non-date Rolex I've had so I've gotten use to a quick set.

Thanks for putting sense to all of this.

I will post pics next. My first vintage.
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Old 19 December 2012, 05:37 PM   #8
swatty
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I think the OP was referring to the hack function ?
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Old 19 December 2012, 02:44 PM   #9
joe100
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Aww crap, my speed read blitz of the topics. Yeah the 7928 didn't have a date. I was thinking 9411.
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Old 20 December 2012, 12:35 AM   #10
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The 390 does not hack! It is a Fleurier automatic movement dating from the 50ies used in the 7928 until the mid 60ies, before Tudor started to use ETA movements. Like the 1030 and the 1520/30/early 60 Rolex movements, there was no hacking function.
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