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9 April 2015, 07:08 AM | #1 |
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Mathematics Question Involving Watches
There is a question whose solution eluded me for years. I occasionally revisited it over time only to be frustrated by not succeeding to solve it by brute force and giving up after a few minutes. Then one night after retiring to bed and revisiting it again, I solved it in 10 or so seconds, without paper and pencil which I never take to bed with me (I'm not that crazy.)
The question is: Determine between 12 noon and 12 midnight, the EXACT times that the minute and hour hands coincide. Express the answers as hours and fractions of hours beyond 12 noon. I will give the solution and proof in this thread in a few weeks after allowing members to ponder this. This can be done in two or three lines. When you see the solution, you will say to yourself, why didn't I think of that! If any member comes up with this elegant (and really beautiful proof), I will recognize it. I will not comment or even look at a number crunching or brute force attempt, valid or invalid. |
9 April 2015, 07:16 AM | #2 |
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Mathematics Question Involving Watches
Read op wrong....deleted
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9 April 2015, 07:18 AM | #3 |
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9 April 2015, 07:25 AM | #4 |
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Seems pretty straightforward to me. Anyway, the position of a watch hand can be thought of as the phase of a sine wave. Create two equations: 1) one that gives you the phase of a 1/60Hz (i.e., revolutions per second) sine wave as a function of time, and 2) one that gives you the phase of a 1/3600Hz (i.e., revolutions per hour) sine wave as a function of time. Now find when the two equations are equal. I'm probably over-thinking this and there probably exists a more elegant solution.
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9 April 2015, 07:32 AM | #5 |
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Is this a trick question?
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9 April 2015, 07:34 AM | #6 |
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No
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9 April 2015, 07:36 AM | #7 |
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9 April 2015, 07:40 AM | #8 |
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At 1:05, the hour hand is no longer pointed at 1. I will no longer comment on incorrect replies.
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9 April 2015, 07:46 AM | #9 |
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9 April 2015, 07:47 AM | #10 |
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9 April 2015, 07:59 AM | #11 |
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Kilyung,
You solved it! That was fast. For those that need an explanation, there are 11 times that the hands coincide in the 12 hour period, not counting the initial position but counting 12 midnight. Moreover the duration between successive coinciding is constant and therefore is 12/11. Kilyung, you rule! |
9 April 2015, 08:05 AM | #12 | |
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Quote:
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9 April 2015, 08:13 AM | #13 | |
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I knew that Caveman is a smart dude!
Quote:
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too much into watches... |
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9 April 2015, 07:54 AM | #14 |
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My head hurts
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9 April 2015, 07:56 AM | #15 |
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9 April 2015, 08:09 AM | #16 |
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In 24 hour scale:
12:00:00 13:05:27 14:10:54 15:16:21 16:21:49 17:27:16 18:32:43 19:38:10 20:43:38 21:49:05 22:54:32 24:00:00
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114060 - 116520 - 126334 |
9 April 2015, 08:00 AM | #17 |
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12 times
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9 April 2015, 08:00 AM | #18 |
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Every 3600 + (3600 / 11) = 3927.272727273 seconds.
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9 April 2015, 08:02 AM | #19 |
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9 April 2015, 08:05 AM | #20 |
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9 April 2015, 08:35 AM | #21 |
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REFZ,
Appreciate the visual representation. However as I am sure you are aware, the tabulated numbers in your table are rounded and not EXACT. |
9 April 2015, 10:44 AM | #22 |
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Yeah...I was going to say that... Nice job, Mike.
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9 April 2015, 12:52 PM | #23 |
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omx5o,
Answer was to be in hours and fractions thereof. You did more work to put it into hours, minutes, and seconds. Your answer however was correct. |
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