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Old Expat Beast · 3 November 2013, 08:16 PM

Been trying to get my head around this thought. As the Milgauss second hand's arrow is slightly offset from the centre of the dial (due to the lightning bolt shape), does it still describe a perfect circle within the circumference of the dial?

Baselman · 3 November 2013, 08:32 PM

Yes the hand length doesn't change in its rotation so perfect circle

padi56 · 3 November 2013, 08:47 PM

Quote:

Originally Posted by Old Expat Beast

Been trying to get my head around this thought. As the Milgauss second hand's arrow is slightly offset from the centre of the dial (due to the lightning bolt shape), does it still describe a perfect circle within the circumference of the dial?

If it moves 360 degrees around the dial then that is a circle no matter the shape of the dial watch hands

Old Expat Beast · 3 November 2013, 08:51 PM

It's illogical I know, but somehow I can't get to grips with a three-stepped hand performing three equal circles within an outer circle. I must be feeble minded.

JGX · 3 November 2013, 09:00 PM

Quote:

Originally Posted by Old Expat Beast

It's illogical I know, but somehow I can't get to grips with a three-stepped hand performing three equal circles within an outer circle. I must be feeble minded.

Does this (very rough and quick photoshop example) help?:

Name: mil.jpg
Views: 231
Size: 273.2 KB

Old Expat Beast · 3 November 2013, 09:05 PM

Quote:

Originally Posted by JGX

Does this help?:

Attachment 437775

Um....kind of. Thanks.

Baselman · 3 November 2013, 09:20 PM

The hand is FIXED the hand length is FIXED the steps are FIXED so every second of rotation equals same position as previous second - law of physics and geometry mean perfect circle rotation.

Cc1966 · 3 November 2013, 11:06 PM

Remember Adam, the lightning bolt hand starts in the center (point A) and ends at the triangle (point B). Now just connect the points mate as the hand is not made of rubber!

Cesium133 · 3 November 2013, 11:20 PM

OP, here's something else to think about...

-The base of the second hand rotates at shorter length than than the arrow at the end. Notice the size of the red circle (base) and the size of the green circle (arrow).

-It takes the entire second hand 60 seconds to make 1 complete rotation. But the arrow end travels a greater distance than the base end, as illustrated in the photo.

-Doesn't that mean the arrow end is traveling at a faster speed than the base end since it covers a greater distance in the same amount of time?

Have fun thinking about that one...

Old Expat Beast · 3 November 2013, 11:39 PM

Quote:

Originally Posted by Cc1966

Remember Adam, the lightning bolt hand starts in the center (point A) and ends at the triangle (point B). Now just connect the points mate as the hand is not made of rubber!

Ok, that works. Thanks

joe100 · 3 November 2013, 11:39 PM

Think about this: if the second hand were long enough, ie VERY long, the end at the cannon pin would be rotating at 60 seconds a minute, but the tip would break the sound barrier.

Don't you just love science?

iazrollie · 3 November 2013, 11:45 PM

Exactly. Yet all points on the hand travel at the same revolutionary speed! Same rpm's at every point on the hand.

Thatguy · 4 November 2013, 01:14 AM

Quote:

Originally Posted by joe100

Think about this: if the second hand were long enough, ie VERY long, the end at the cannon pin would be rotating at 60 seconds a minute, but the tip would break the sound barrier.

Don't you just love science?

True,but how long would it have to be? Anyone feel like doing the math?

joe100 · 4 November 2013, 02:17 AM

Quote:

Originally Posted by Thatguy

True,but how long would it have to be? Anyone feel like doing the math?

It's an easy formula:
a = v2
__
r

The speed of sound at sea level is 1,126 fps

Solve for r

Good luck!

3 November 2013, 08:16 PM	#1
Old Expat Beast TRF Moderator & 2024 SubLV41 Patron Join Date: Jul 2013 Real Name: Adam Location: Far East Watch: Golden Tuna Posts: 28,826	A perfect circle? Been trying to get my head around this thought. As the Milgauss second hand's arrow is slightly offset from the centre of the dial (due to the lightning bolt shape), does it still describe a perfect circle within the circumference of the dial? __________________ _______________________

3 November 2013, 08:51 PM	#4
Old Expat Beast TRF Moderator & 2024 SubLV41 Patron Join Date: Jul 2013 Real Name: Adam Location: Far East Watch: Golden Tuna Posts: 28,826	It's illogical I know, but somehow I can't get to grips with a three-stepped hand performing three equal circles within an outer circle. I must be feeble minded. __________________ _______________________

3 November 2013, 11:06 PM	#8
Cc1966 "TRF" Member Join Date: Aug 2013 Real Name: Christopher Location: Georgia, USA Watch: ing the Sea... Posts: 6,713	Remember Adam, the lightning bolt hand starts in the center (point A) and ends at the triangle (point B). Now just connect the points mate as the hand is not made of rubber! __________________ "I wish to have no Connection with any Ship that does not Sail fast for I intend to go in harm's way." Captain John Paul Jones, 16 November 1778 "*Curmudgeons* " Favorites: 1665 SD, Sub Date, DSSD, Exp II, Sub LV, GMTIIc

3 November 2013, 11:39 PM	#11
joe100 2024 SubLV41 Pledge Member Join Date: Nov 2007 Real Name: Joe Location: New Mexico Watch: Explorer Posts: 12,840	Think about this: if the second hand were long enough, ie VERY long, the end at the cannon pin would be rotating at 60 seconds a minute, but the tip would break the sound barrier. Don't you just love science? __________________ It's Espresso, not Expresso. Coffee is not a train in Italy. -TRF Member 6982-

3 November 2013, 11:45 PM	#12
iazrollie "TRF" Member Join Date: Jul 2013 Real Name: Ian Location: NY Watch: All of them Posts: 3,245	Exactly. Yet all points on the hand travel at the same revolutionary speed! Same rpm's at every point on the hand. __________________ Rolex, PPs, Breitling

3 November 2013, 08:32 PM	#2
Baselman "TRF" Member Join Date: May 2013 Location: Switzerland Watch: 1665 GreatWhite SD Posts: 1,527	Yes the hand length doesn't change in its rotation so perfect circle

3 November 2013, 09:20 PM	#7
Baselman "TRF" Member Join Date: May 2013 Location: Switzerland Watch: 1665 GreatWhite SD Posts: 1,527	The hand is FIXED the hand length is FIXED the steps are FIXED so every second of rotation equals same position as previous second - law of physics and geometry mean perfect circle rotation.

3 November 2013, 11:20 PM	#9
Cesium133 "TRF" Member Join Date: Sep 2012 Location: USA Posts: 2,037	OP, here's something else to think about... -The base of the second hand rotates at shorter length than than the arrow at the end. Notice the size of the red circle (base) and the size of the green circle (arrow). -It takes the entire second hand 60 seconds to make 1 complete rotation. But the arrow end travels a greater distance than the base end, as illustrated in the photo. -Doesn't that mean the arrow end is traveling at a faster speed than the base end since it covers a greater distance in the same amount of time? Have fun thinking about that one...

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